KCET · Physics · Current Electricity
Potential difference between \( A \) and \( B \) in the following circuit
- A \( 4 \mathrm{~V} \)
- B \( 5.6 \mathrm{~V} \)
- C \( 2.8 \mathrm{~V} \)
- D \( 6 \mathrm{~V} \)
Answer & Solution
Correct Answer
(B) \( 5.6 \mathrm{~V} \)
Step-by-step Solution
Detailed explanation
Current,
\( I=\frac{E}{R+r}=\frac{6 V-4 V}{8 \Omega+2 \Omega}=\frac{2 V}{10 \Omega}=0.2 A \)
Potential difference across \( 8 \Omega \) resistor is
\( V=I \times R=0.2 \times 8 \Omega=1.6 \mathrm{~V} \)
Thus, potential difference across A and B is
\( V+4=(1.6+4)=5.6 \mathrm{~V} \)
\( I=\frac{E}{R+r}=\frac{6 V-4 V}{8 \Omega+2 \Omega}=\frac{2 V}{10 \Omega}=0.2 A \)
Potential difference across \( 8 \Omega \) resistor is
\( V=I \times R=0.2 \times 8 \Omega=1.6 \mathrm{~V} \)
Thus, potential difference across A and B is
\( V+4=(1.6+4)=5.6 \mathrm{~V} \)
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