KCET · Physics · Magnetic Properties of Matter
From the following graph of photo current against collector plate potential, for two different intensities of light \( I_{1} \) and \( I_{2} \), one can conclude

- A \( O I_{1}=I_{2} \)
- B \( I_{1}>I_{2} \)
- C \( I_{1} < I_{2} \)
- D Comparison is not possible.
Answer & Solution
Correct Answer
(C) \( I_{1} < I_{2} \)
Step-by-step Solution
Detailed explanation
For a fixed frequency of incident light, photo-current is directly proportional to the intensity.
Thus, from graph, photo current for light of Intensity \( I_{2} \) is more than for light of intensity \( I_{1} \), Therefore, \( I_{1} < I_{2} \)
Thus, from graph, photo current for light of Intensity \( I_{2} \) is more than for light of intensity \( I_{1} \), Therefore, \( I_{1} < I_{2} \)
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