KCET · Physics · Magnetic Properties of Matter
A current of \(\left(\frac{2}{\sqrt{3}}\right)\) A, produces a deflection of \(60^{\circ}\) in a tangent galvanometer. The reduction factor is
- A \(\left(\frac{2}{\sqrt{3}}\right) \mathrm{A}\)
- B \(\left(\frac{2}{3}\right) \mathrm{A}\)
- C \(2 \mathrm{~A}\)
- D \(\left(\frac{3}{2}\right) \mathrm{A}\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{2}{3}\right) \mathrm{A}\)
Step-by-step Solution
Detailed explanation
For tangent galvanometer
\(I =K \tan \theta\)
\(K=\frac{I}{\tan \theta}\)
\(K=\frac{2 / \sqrt{3}}{\tan 60^{\circ}}\)
\(K =\frac{2}{3} \mathrm{~A}\)
\(I =K \tan \theta\)
\(K=\frac{I}{\tan \theta}\)
\(K=\frac{2 / \sqrt{3}}{\tan 60^{\circ}}\)
\(K =\frac{2}{3} \mathrm{~A}\)
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