KCET · Physics · Electrostatics
A certain charge 2Q is divided at first into two parts \( q_{1} \) and \( q_{2} . \) Later the charges are placed at a certain distance. If the force of interaction between two charges is maximum then \( \frac{Q}{q_{1}} \)
- A \( 1 \)
- B \( 04 \)
- C \( 0.5 \)
- D \( 12 \)
Answer & Solution
Correct Answer
(A) \( 1 \)
Step-by-step Solution
Detailed explanation
(A)
For force \( \mathrm{F} \) to be maximum between charges \( q_{1} \) and \( q_{2}, q_{1}=q_{2}=\frac{2 Q}{2}=Q \)
Now \( \frac{Q}{q_{1}}=\frac{Q}{Q}=1 \)
For force \( \mathrm{F} \) to be maximum between charges \( q_{1} \) and \( q_{2}, q_{1}=q_{2}=\frac{2 Q}{2}=Q \)
Now \( \frac{Q}{q_{1}}=\frac{Q}{Q}=1 \)
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