KCET · Maths · Differentiation
If \( x=\operatorname{asec}^{2} \theta, y=\operatorname{atan}^{2} \theta \) then \( \frac{d^{2} y}{d x^{2}}= \)
- A \( 11 \)
- B \( 04 \)
- C \( 2 a \)
- D \( 00 \)
Answer & Solution
Correct Answer
(D) \( 00 \)
Step-by-step Solution
Detailed explanation
\( (D) \)
\( \frac{d x}{d \theta}=2 a \sec ^{2} \theta \tan \theta \)
\( \frac{d y}{d \theta}=2 a \tan \theta \sec ^{2} \theta \)
\( \therefore \frac{d y}{d x}=\frac{d y}{d x}=\frac{2 a \tan \theta \sec ^{2} \theta}{2 a \tan \theta \sec ^{2} \theta}=1 \)
\( \therefore \frac{d^{2} y}{d x^{2}}=0 \)
\( \frac{d x}{d \theta}=2 a \sec ^{2} \theta \tan \theta \)
\( \frac{d y}{d \theta}=2 a \tan \theta \sec ^{2} \theta \)
\( \therefore \frac{d y}{d x}=\frac{d y}{d x}=\frac{2 a \tan \theta \sec ^{2} \theta}{2 a \tan \theta \sec ^{2} \theta}=1 \)
\( \therefore \frac{d^{2} y}{d x^{2}}=0 \)
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