KCET · Maths · Limits
\(\lim _{x \rightarrow \frac{\pi}{4}} \frac{\sqrt{2} \cos x-1}{\cot x-1}\) is equal to
- A \(2\)
- B \(\sqrt{2}\)
- C \(1 / 2\)
- D \(1 / \sqrt{2}\)
Answer & Solution
Correct Answer
(C) \(1 / 2\)
Step-by-step Solution
Detailed explanation
\(\because \lim _{x \rightarrow \frac{\pi}{4}} \frac{\sqrt{2} \cos x-1}{\cot x-1}\)
\(=\lim _{x \rightarrow \frac{\pi}{4}} \frac{-\sqrt{2} \sin x}{-\operatorname{cosec}^2 x}\) [using L-Hospital rule]
\(=\frac{-\sqrt{2} \times \frac{1}{\sqrt{2}}}{-2}=\frac{1}{2}\)
\(=\lim _{x \rightarrow \frac{\pi}{4}} \frac{-\sqrt{2} \sin x}{-\operatorname{cosec}^2 x}\) [using L-Hospital rule]
\(=\frac{-\sqrt{2} \times \frac{1}{\sqrt{2}}}{-2}=\frac{1}{2}\)
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