KCET · Maths · Determinants
If the value of a third order determinant is \( 16 \), then the value of the determinant formed by
replacing each of its elements by its co factor is
- A (18)
- B \( 16 \)
- C \( 96 \)
- D \( 256 \)
Answer & Solution
Correct Answer
(D) \( 256 \)
Step-by-step Solution
Detailed explanation
\( (\mathrm{D}) \)
\( |\mathrm{A}|=16, \mathrm{O}(\mathrm{A})=3 \)
\( |\operatorname{adj} \mathrm{A}|=|A|^{2} \)
\( =16^{2} \)
\( =256 \)
\( |\mathrm{A}|=16, \mathrm{O}(\mathrm{A})=3 \)
\( |\operatorname{adj} \mathrm{A}|=|A|^{2} \)
\( =16^{2} \)
\( =256 \)
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