KCET · Maths · Probability
Two cards are drawn at random from a pack of \( 52 \) cards. The probability of these two being
'Aces" is
- A \( \frac{1}{26} \)
- B \( \frac{1}{221} \)
- C \( \frac{1}{2} \)
- D \( \frac{1}{13} \)
Answer & Solution
Correct Answer
(B) \( \frac{1}{221} \)
Step-by-step Solution
Detailed explanation
Total number of Aces in a pack is \( 4 . \)
So, required probability is
\( P(2 \) aces \( )=\frac{{ }^{4} C_{2}}{{ }^{52} C_{2}} \) \( =\frac{4 \times 3}{52 \times 51}=\frac{1}{221} \)
So, required probability is
\( P(2 \) aces \( )=\frac{{ }^{4} C_{2}}{{ }^{52} C_{2}} \) \( =\frac{4 \times 3}{52 \times 51}=\frac{1}{221} \)
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