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KCET · Maths · Mathematical Reasoning

The eccentricity of the ellipse \( \frac{x^{2}}{36}+\frac{y^{2}}{16}=1 \) is

  1. A \( \frac{2 \sqrt{5}}{6} \)
  2. B \( \frac{2 \sqrt{5}}{4} \)
  3. C \( \frac{2 \sqrt{13}}{6} \)
  4. D \( \frac{2 \sqrt{13}}{4} \)
Verified Solution

Answer & Solution

Correct Answer

(A) \( \frac{2 \sqrt{5}}{6} \)

Step-by-step Solution

Detailed explanation

Given equation of ellipse,
\[
\frac{x^{2}}{36}+\frac{y^{2}}{16}=1
\]
We know that eccentricity is given by,
\[
e=\sqrt{\frac{a^{2}-b^{2}}{a^{2}}}
\]
\[
\begin{array}{l}
\text { Here } a^{2}=36 \text { and } b^{2}=16 \\
\text { So, } e=\sqrt{\frac{36-16}{36}}=\frac{2 \sqrt{5}}{6}
\end{array}
\]