KCET · Maths · Straight Lines
The centroid of the triangle \(\mathrm{ABC}\), where \(A \equiv(2,3), B \equiv(8,10)\) and \(C \equiv(5,5)\) is
- A \((5,6)\)
- B \((6,5)\)
- C \((6,6)\)
- D \((15,18)\)
Answer & Solution
Correct Answer
(A) \((5,6)\)
Step-by-step Solution
Detailed explanation
Since, the vertices of the triangle are \(A \equiv(2,3), B \equiv(8,10)\) and \(C \equiv(5,5)\).
\(\therefore\) The centroid of
\[
\Delta \mathrm{ABC}=\left(\frac{2+8+5}{3}, \frac{3+10+5}{3}\right)=(5,6)
\]
\(\therefore\) The centroid of
\[
\Delta \mathrm{ABC}=\left(\frac{2+8+5}{3}, \frac{3+10+5}{3}\right)=(5,6)
\]
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