KCET · Maths · Pair of Lines
The angle between the pair of lines \(x^{2}+2 x y-y^{2}=0\) is
- A \(\frac{\pi}{6}\)
- B \(\frac{\pi}{2}\)
- C 0
- D \(\frac{\pi}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
Given pair of lines is \(x^{2}+2 x y-y^{2}=0\)
Here, \(\mathrm{a}=1, \quad \mathrm{~b}=-1, \quad \mathrm{~h}=1\)
Now, \(a+b=1-1=0\)
Hence, given pair of lines are perpendicular.
Here, \(\mathrm{a}=1, \quad \mathrm{~b}=-1, \quad \mathrm{~h}=1\)
Now, \(a+b=1-1=0\)
Hence, given pair of lines are perpendicular.
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