KCET · Maths · Vector Algebra
If \(\mathbf{a}, \mathbf{b}\) and \(\mathbf{c}\) are three non-coplanar vectors and
\(\mathbf{p}, \mathbf{q}\) and \(\mathbf{r}\) are vectors defined by \(\mathbf{p}=\frac{\mathbf{b} \times \mathbf{c}}{[\mathbf{a} \mathbf{b} \mathbf{c}]}, \mathbf{q}=\frac{\mathbf{c} \times \mathbf{a}}{[\mathbf{a} \mathbf{b} \mathbf{c}]}\) and \(\mathbf{r}=\frac{\mathbf{a} \times \mathbf{b}}{[\mathbf{a} \mathbf{b} \mathbf{c}]}\), then the value of \((\mathbf{a}+\mathbf{b}) \cdot \mathbf{p}+(\mathbf{b}+\mathbf{c}) \cdot \mathbf{q}+(\mathbf{c}+\mathbf{a}) \cdot \mathbf{r}\) is equal to
- A 0
- B 1
- C 2
- D 3
Answer & Solution
Correct Answer
(D) 3
Step-by-step Solution
Detailed explanation
Let \(\mathrm{T}_{1}=(\mathbf{a}+\mathbf{b}) \cdot \mathbf{p}\)
\(=\mathbf{a} \cdot \mathbf{p}+\mathbf{b} \cdot \mathbf{p}\)
\(=\mathbf{a} \cdot \frac{\mathbf{b} \times \mathbf{c}}{[\mathbf{a} \mathbf{b} \mathbf{c}]}+\frac{\mathbf{b} \cdot(\mathbf{b} \times \mathbf{c})}{[\mathbf{a} \mathbf{b} \mathbf{c}]}\)
\(=\frac{[\mathbf{a} \mathbf{b} \mathbf{c}]}{[\mathbf{a} \mathbf{b} \mathbf{c}]}+\frac{[\mathbf{b} \mathbf{b} \mathbf{c}]}{[\mathbf{a} \mathbf{b} \mathbf{c}]}=1+0=1\)
Similarly, \(\mathrm{T}_{2}=(\mathbf{b}+\mathbf{c}) \cdot \mathbf{q}=1\)
and \(\quad \mathrm{T}_{3}=(\mathbf{c}+\mathbf{a}) \cdot \mathbf{r}=1\)
\(\therefore \quad \mathrm{T}_{1}+\mathrm{T}_{2}+\mathrm{T}_{3}=3\)
\(=\mathbf{a} \cdot \mathbf{p}+\mathbf{b} \cdot \mathbf{p}\)
\(=\mathbf{a} \cdot \frac{\mathbf{b} \times \mathbf{c}}{[\mathbf{a} \mathbf{b} \mathbf{c}]}+\frac{\mathbf{b} \cdot(\mathbf{b} \times \mathbf{c})}{[\mathbf{a} \mathbf{b} \mathbf{c}]}\)
\(=\frac{[\mathbf{a} \mathbf{b} \mathbf{c}]}{[\mathbf{a} \mathbf{b} \mathbf{c}]}+\frac{[\mathbf{b} \mathbf{b} \mathbf{c}]}{[\mathbf{a} \mathbf{b} \mathbf{c}]}=1+0=1\)
Similarly, \(\mathrm{T}_{2}=(\mathbf{b}+\mathbf{c}) \cdot \mathbf{q}=1\)
and \(\quad \mathrm{T}_{3}=(\mathbf{c}+\mathbf{a}) \cdot \mathbf{r}=1\)
\(\therefore \quad \mathrm{T}_{1}+\mathrm{T}_{2}+\mathrm{T}_{3}=3\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- The tangent to the curve \(x y=25\) at any point on it cuts the coordinate axes at \(A\) and \(B\), then the area of the \(\triangle \mathrm{OAB}\) isKCET 2012 Hard
- If \(\mathrm{n}=(2020)\) ! then
\[
\frac{1}{\log _{2} n}+\frac{1}{\log _{3} n}+\frac{1}{\log _{4} n}+\ldots+\frac{1}{\log _{2020} n}
\]
is equal toKCET 2009 Medium - The value of \(\cos 1200^{\circ}+\tan 1485^{\circ}\) isKCET 2021 Easy
- Solution of differential equating \(x d y-y d x=0\) representsKCET 2021 Easy
- The sum of two positive numbers is given. If the sum of their cubes is minimum, thenKCET 2012 Hard
- How many ways can you arrange all the letters and numbers in "KCET 2025" which start with K and end with \(5\)?KCET 2026 Easy
More PYQs from KCET
- A variable line \(\frac{x}{a}+\frac{y}{b}=1\) is such that \(a+b=4\). The locus of the mid point of the portion of the line intercepted between the axes isKCET 2008 Hard
- Two finite sets have \(m\) and \(n\) elements respectively. The total number of subsets of the first set is 56 more than the total number of subsets of the second set. The values of \(m\) and \(n\), respectively areKCET 2024 Easy
- \( \sim[(-p) \wedge q] \) is logically equivalent toKCET 2015 Easy
- Which of the following statements is not true?KCET 2025 Easy
- A compound of 'A' and 'B' crystallises in a cubic lattice in which 'A' atoms occupy the lattice points at the corners of the cube. The ' \(B\) ' atoms occupy the centre of each face of the cube. The probable empirical formula of the compound isKCET 2009 Medium
- If \(f(x)=\log _{x^{2}}\left(\log _{e} x\right)\), then \(f^{\prime}(x)\) at \(x=e\) isKCET 2009 Hard