KCET · Chemistry · Chemical Kinetics
Time required for 100 per cent completion of a zero order reaction is
- A \(\frac{2 k}{a}\)
- B \(\frac{\mathrm{a}}{2 \mathrm{k}}\)
- C \(\frac{\mathrm{a}}{\mathrm{k}}\)
- D ak
Answer & Solution
Correct Answer
(C) \(\frac{\mathrm{a}}{\mathrm{k}}\)
Step-by-step Solution
Detailed explanation
For zero order reactions,
\[
[\mathrm{A}]=-\mathrm{kt}+[\mathrm{A}]_{0}
\]
where, \([\mathrm{A}]_{0}=\) initial concentration \(=\mathrm{a}\)
\([\mathrm{A}]=\) remaining concentration \(=\mathrm{a}-\mathrm{a}=0\)
On putting values of \([\mathrm{A}]_{0}\) and \([\mathrm{A}]\), we get
\[
\mathrm{t}=\frac{\mathrm{a}}{\mathrm{k}}
\]
\[
[\mathrm{A}]=-\mathrm{kt}+[\mathrm{A}]_{0}
\]
where, \([\mathrm{A}]_{0}=\) initial concentration \(=\mathrm{a}\)
\([\mathrm{A}]=\) remaining concentration \(=\mathrm{a}-\mathrm{a}=0\)
On putting values of \([\mathrm{A}]_{0}\) and \([\mathrm{A}]\), we get
\[
\mathrm{t}=\frac{\mathrm{a}}{\mathrm{k}}
\]
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