KCET · Chemistry · Chemical Bonding and Molecular Structure
The percentage of \(p\)-character of the hybrid orbitals in graphite and diamond are respectively
- A 50 and 75
- B 67 and 75
- C 33 and 75
- D 33 and 25
Answer & Solution
Correct Answer
(B) 67 and 75
Step-by-step Solution
Detailed explanation
In graphite, C-atom is \(\mathrm{sp}^{2}\) hybridised.
\(\therefore\) p-character \(=\frac{2}{3} \times 100 \approx 67 \%\)
Again in diamond, C-atom is \(\mathrm{sp}^{3}\) hybridised.
\(\therefore\) p-character \(=\frac{3}{4} \times 100=75 \%\)
\(\therefore\) p-character \(=\frac{2}{3} \times 100 \approx 67 \%\)
Again in diamond, C-atom is \(\mathrm{sp}^{3}\) hybridised.
\(\therefore\) p-character \(=\frac{3}{4} \times 100=75 \%\)
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