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KCET · Chemistry · Structure of Atom

A body of mass \(x \mathrm{~kg}\) is moving with a velocity of \(100 \mathrm{~ms}^{-1}\). Its de-Broglie wavelength is \(6.62 \times 10^{-35} \mathrm{~m}\). Hence, \(\mathrm{x}\) is \(\left(\mathrm{h}=6.62 \times 10^{-34} \mathrm{Js}\right.\) )

  1. A \(0.1 \mathrm{~kg}\)
  2. B \(0.25 \mathrm{~kg}\)
  3. C \(0.15 \mathrm{~kg}\)
  4. D \(0.2 \mathrm{~kg}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.1 \mathrm{~kg}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} \lambda &=\frac{\mathrm{h}}{\mathrm{mv}} \\ &=\frac{6.62 \times 10^{-34}}{6.62 \times 10^{-35} \times 100} \\ &=0.1 \mathrm{~kg} \end{aligned}\)