KCET · Chemistry · Structure of Atom
A body of mass \(x \mathrm{~kg}\) is moving with a velocity of \(100 \mathrm{~ms}^{-1}\). Its de-Broglie wavelength is \(6.62 \times 10^{-35} \mathrm{~m}\). Hence, \(\mathrm{x}\) is \(\left(\mathrm{h}=6.62 \times 10^{-34} \mathrm{Js}\right.\) )
- A \(0.1 \mathrm{~kg}\)
- B \(0.25 \mathrm{~kg}\)
- C \(0.15 \mathrm{~kg}\)
- D \(0.2 \mathrm{~kg}\)
Answer & Solution
Correct Answer
(A) \(0.1 \mathrm{~kg}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \lambda &=\frac{\mathrm{h}}{\mathrm{mv}} \\ &=\frac{6.62 \times 10^{-34}}{6.62 \times 10^{-35} \times 100} \\ &=0.1 \mathrm{~kg} \end{aligned}\)
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