KCET · Chemistry · d and f Block Elements
The electronic configuration of \(\mathrm{Cu}^{2+}\) ion is
- A \([\mathrm{Ar}] 3 d^{8} 4 s^{1}\)
- B \([\mathrm{Ar}] 3 d^{9} 4 \mathrm{~s}^{0}\)
- C \([\mathrm{Ar}] 3 d^{7} 4 s^{2}\)
- D \([\mathrm{Ar}] 3 d^{8} 4 s^{0}\)
Answer & Solution
Correct Answer
(B) \([\mathrm{Ar}] 3 d^{9} 4 \mathrm{~s}^{0}\)
Step-by-step Solution
Detailed explanation
Electronic configuration of copper and cupric ion
\(\begin{aligned}
&\mathrm{Cu}(Z=29)=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{1} \\
&\mathrm{Cu}^{2+} \text { (cupric ion) }=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{9} 4 s^{0}
\end{aligned}\)
or

\(\begin{aligned}
&\mathrm{Cu}(Z=29)=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{1} \\
&\mathrm{Cu}^{2+} \text { (cupric ion) }=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{9} 4 s^{0}
\end{aligned}\)
or

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