KCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
The correct decreasing order of basicity of hydrides of group- 15 elements is
- A \(\mathrm{SbH}_3>\mathrm{AsH}_3>\mathrm{PH}_3>\mathrm{NH}_3\)
- B \(\mathrm{PH}_3>\mathrm{AsH}_3>\mathrm{SbH}_3>\mathrm{NH}_3\)
- C \(\mathrm{AsH}_3>\mathrm{SbH}_3>\mathrm{NH}_3>\mathrm{PH}_3\)
- D \(\mathrm{NH}_3>\mathrm{PH}_3>\mathrm{AsH}_3>\mathrm{SbH}_3\)
Answer & Solution
Correct Answer
(D) \(\mathrm{NH}_3>\mathrm{PH}_3>\mathrm{AsH}_3>\mathrm{SbH}_3\)
Step-by-step Solution
Detailed explanation
In general, the basicity of group 15 hydrides
decreases on moving down the group from \(\mathrm{NH}_3\) to \(\mathrm{SbH}_3\). This is due to the increasing size of the central atom and the decreasing availability of lone pair for donation. Thus, the correct order of basicity of hydrides is
\(\mathrm{NH}_3>\mathrm{PH}_3>\mathrm{AsH}_3>\mathrm{SbH}_3\)
decreases on moving down the group from \(\mathrm{NH}_3\) to \(\mathrm{SbH}_3\). This is due to the increasing size of the central atom and the decreasing availability of lone pair for donation. Thus, the correct order of basicity of hydrides is
\(\mathrm{NH}_3>\mathrm{PH}_3>\mathrm{AsH}_3>\mathrm{SbH}_3\)
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