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KCET · Chemistry · Chemical Equilibrium

Match the following pKa values.
\(\begin{array}{|l|l|}
\hline Acid & pKa \\
\hline (a) Phenol & (i) 16 \\
\hline (b) p-Nitrophenol & (ii) 0.78 \\
\hline (c) Ethanol & (iii) 10 \\
\hline (d) Picric acid & (iv) 7.1 \\
\hline
\end{array}\)

  1. A \(\begin{array}{llll}a & b & c & d\end{array}\)
  2. B \( \begin{array}{llll}a & b & c & d \\ \text { iv } & \text { ii } & \text { iii } & \text { i }\end{array} \)
  3. C \( \begin{array}{llll}a & b & c & d \\ \text { iii } & \text { iv } & \text { i } & \text { ii }\end{array} \)
  4. D \( \begin{array}{llll}a & b & c & d \\ i i & i & i i & i v\end{array} \)
Verified Solution

Answer & Solution

Correct Answer

(C) \( \begin{array}{llll}a & b & c & d \\ \text { iii } & \text { iv } & \text { i } & \text { ii }\end{array} \)

Step-by-step Solution

Detailed explanation

The compound will be more acidic when its conjugate base is more stable. In case of these given compounds, more the
electron with the drawing group, present more the compound will be more acidic.