KCET · Chemistry · Coordination Compounds
If a didentate ligand ethane-1, 2-diamine is progressively added in the molar ratio en : \(\mathrm{Ni}\) \(:: 1: 1,2: 1,3: 1\) to \(\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}\) aq solution, following co-ordination entities are formed.
I. \(\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_4 \mathrm{en}\right]^{2+}(a q)-\) pale blue
II. \(\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_2(\mathrm{en})_2\right]^{2+}(a q)-\) blue/purple
III. \(\left[\mathrm{Ni}(\mathrm{en})_3\right]^{2+}(\mathrm{aq})\) - violet
The wavelength in \(\mathrm{nm}\) of light absorbed in case of I and III are respectively
- A \(475 \mathrm{~nm}\) and \(310 \mathrm{~nm}\)
- B \(300 \mathrm{~nm}\) and \(475 \mathrm{~nm}\)
- C \(310 \mathrm{~nm}\) and \(500 \mathrm{~nm}\)
- D \(600 \mathrm{~nm}\) and \(535 \mathrm{~nm}\)
Answer & Solution
Correct Answer
(D) \(600 \mathrm{~nm}\) and \(535 \mathrm{~nm}\)
Step-by-step Solution
Detailed explanation
Given that, compound I shows pale blue
colour. It means that, absorbed colour is orange whereas compound III shows violet colour then the absorbed colour is yellow. The wavelength of light absorbed by I and III are nearly \(600 \mathrm{~nm}\) and \(535 \mathrm{~nm}\) respectively.
colour. It means that, absorbed colour is orange whereas compound III shows violet colour then the absorbed colour is yellow. The wavelength of light absorbed by I and III are nearly \(600 \mathrm{~nm}\) and \(535 \mathrm{~nm}\) respectively.
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