KCET · Chemistry · p Block Elements (Group 13 & 14)
Hybridised states of carbon in graphite and diamond are respectively
- A \(s p^{3}, s p^{3}\)
- B \(s p^{3}, s p^{2}\)
- C \(s p^{2}, s p^{2}\)
- D \(s p^{2}, s p^{3}\)
Answer & Solution
Correct Answer
(D) \(s p^{2}, s p^{3}\)
Step-by-step Solution
Detailed explanation
In graphite, carbon is \(s p^{2}\) hybridised. Each carbon is thus linked to three other carbon atoms forming hexagonal rings. On the other hand, in diamond carbon is \(s p^{3}\) hybridised. Each carbon is tetrahedrally linked to four strong C-C, \(s p^{3}-s p^{3} \sigma\)-bonds.
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