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KCET · Chemistry · General Principles and Processes of Isolation of Metals

From the Ellingham graphs on carbon, which of the following statements is false?

  1. A \(\mathrm{CO}\) reduces \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) to \(\mathrm{Fe}\) at less than \(983 \mathrm{~K}\)
  2. B \(\mathrm{CO}\) is less stable than \(\mathrm{CO}_{2}\) at more than \(983 \mathrm{~K}\)
  3. C \(\mathrm{CO}\) reduces \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) to \(\mathrm{Fe}\) in the reduction zone of blast furnace
  4. D \(\mathrm{CO}_{2}\) is more stable than \(\mathrm{CO}\) at less than \(983 \mathrm{~K}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\mathrm{CO}\) is less stable than \(\mathrm{CO}_{2}\) at more than \(983 \mathrm{~K}\)

Step-by-step Solution

Detailed explanation

In Ellingham graph, initially the \(\Delta_{\mathrm{f}} \mathrm{G}^{\circ}\) more negative for \(\mathrm{CO}_{2}\), thus, \(\mathrm{CO}_{2}\) is more stable than CO but when the temperature becomes \(983 \mathrm{~K}\), the conditions inverted i.e., \(\Delta_{f} \mathrm{G}^{\circ}\) of \(\mathrm{CO}\) becomes more negative and hence above \(983 \mathrm{~K}\), CO becomes more stable than \(\mathrm{CO}_{2}\).