KCET · Chemistry · Thermodynamics (C)
Based on the first law of thermodynamics, which one of the following is correct?
- A For an isochoric process \(=\Delta \mathrm{E}=-\mathrm{q}\)
- B For an adiabatic process \(=\Delta \mathrm{E}=-\mathrm{W}\)
- C For an isothermal process \(=\mathrm{q}=+\mathrm{w}\)
- D For a cyclic process \(q=-w\)
Answer & Solution
Correct Answer
(D) For a cyclic process \(q=-w\)
Step-by-step Solution
Detailed explanation
First law of Thermodynamics is
\[
\Delta \mathrm{E}=\mathrm{Q}+\mathrm{W}
\]
(a) For isochoric process, \(\Delta V=0\)
\[
\mathrm{W}=\mathrm{p} \Delta \mathrm{V}=0
\]
\(\therefore\)
\[
\Delta \mathrm{E}=\mathrm{Q}
\]
(b) For adiabatic process, \(Q=0\)
\[
\Delta \mathrm{E}=\mathrm{W}
\]
(c) For isothermal process, \(\Delta \mathrm{T}=0\) and
\[
\begin{aligned}
\Delta \mathrm{E} &=0 \\
\mathrm{Q} &=-\mathrm{W}
\end{aligned}
\]
(d) For cyclic process, state functions like
\[
\begin{aligned}
\Delta \mathrm{E} &=0 \\
\mathrm{Q} &=-W
\end{aligned}
\]
\[
\Delta \mathrm{E}=\mathrm{Q}+\mathrm{W}
\]
(a) For isochoric process, \(\Delta V=0\)
\[
\mathrm{W}=\mathrm{p} \Delta \mathrm{V}=0
\]
\(\therefore\)
\[
\Delta \mathrm{E}=\mathrm{Q}
\]
(b) For adiabatic process, \(Q=0\)
\[
\Delta \mathrm{E}=\mathrm{W}
\]
(c) For isothermal process, \(\Delta \mathrm{T}=0\) and
\[
\begin{aligned}
\Delta \mathrm{E} &=0 \\
\mathrm{Q} &=-\mathrm{W}
\end{aligned}
\]
(d) For cyclic process, state functions like
\[
\begin{aligned}
\Delta \mathrm{E} &=0 \\
\mathrm{Q} &=-W
\end{aligned}
\]
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