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KCET · Chemistry · Chemical Kinetics

A first order reaction is \(60 \%\) complete in 20 minutes. How long will the reaction take to be \(84 \%\) complete?

  1. A \(68 \mathrm{~min}\)
  2. B \(40 \mathrm{~min}\)
  3. C \(76 \mathrm{~min}\)
  4. D \(54 \mathrm{~min}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(40 \mathrm{~min}\)

Step-by-step Solution

Detailed explanation

For a first order reaction,
\[
k=\frac{2.303}{t} \log \frac{a}{a-x}
\]
I Case
\(k=\frac{2.303}{20} \log \frac{100}{100-60}\)
\[
=\frac{2.303}{20} \log \frac{100}{40}
\]
\[
\begin{aligned}
&=\frac{2.303}{20}(\log 10-\log 4) \\
&=\frac{2.303}{20}(1-0.6020)=0.046
\end{aligned}
\]
II Case
\[
\begin{aligned}
k &=\frac{2.303}{t} \log \frac{100}{100-84} \\
t=& \frac{2.303}{0.046} \log \frac{100}{16} \\
&=\frac{2.303}{0.046}(\log 100-\log 16) \\
&=\frac{2.303}{0.046}(2-1.2041) \\
&=39.84 \mathrm{~min}=40 \mathrm{~min}
\end{aligned}
\]