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KCET · Chemistry · Electrochemistry

A current of 3 A is passed through a molten calcium salt for 1 hr 47 min 13 s . The mass of calcium deposited is
(Molar mass of \(\mathrm{Ca}=40 \mathrm{~g} \mathrm{~mol}^{-1}\) )

  1. A 6.0 g
  2. B 2.0 g
  3. C 8.0 g
  4. D 4.0 g
Verified Solution

Answer & Solution

Correct Answer

(D) 4.0 g

Step-by-step Solution

Detailed explanation

Given,
\(t=1 \mathrm{hr} 47 \mathrm{~min} 13 \mathrm{sec}=6433\) seconds
Molar mass of \(\mathrm{Ca}=40 \mathrm{~g} / \mathrm{mol}\)
Current \((i)=3 A\)
Mass of calcium deposited \((w)=\) ?
Using Faraday's \(2^{\text {nd }}\) law
\(w=z i t\) ....(i)
where, \(z=\frac{M}{n \times 96500}=\frac{40}{2 \times 96500}\)
Substitute the value of \(Z\) and given values in equation (i)
\(W=\frac{40 \times 3 \times 6433}{2 \times 96500}=3.99 \mathrm{~g} \approx 4 \mathrm{~g}\)