KCET · Chemistry · Some Basic Concepts of Chemistry
\(80 \mathrm{~g}\) of oxygen contains as many atoms as in
- A \(80 \mathrm{~g}\) of hydrogen
- B \(1 \mathrm{~g}\) of hydrogen
- C \(10 \mathrm{~g}\) of hydrogen
- D \(5 \mathrm{~g}\) of hydrogen
Answer & Solution
Correct Answer
(D) \(5 \mathrm{~g}\) of hydrogen
Step-by-step Solution
Detailed explanation
Number of moles of oxygen \(=\frac{80}{16}\)
Number of atoms of oxygen \(=\frac{80}{16} \times \mathrm{N}_{0} \times 2\)
\[
=5 \times \mathrm{N}_{0} \times 2
\]
Number of moles of \(5 \mathrm{~g}\) of hydrogen \(=\frac{5}{1}\)
Number of atoms in \(5 \mathrm{~g}\) of hydrogen \(=5 \times \mathrm{N}_{0} \times 2\)
Hence, the number of atoms in \(80 \mathrm{~g}\) of oxygen is equal to the number of atoms in \(5 \mathrm{~g}\) of hydrogen.
Number of atoms of oxygen \(=\frac{80}{16} \times \mathrm{N}_{0} \times 2\)
\[
=5 \times \mathrm{N}_{0} \times 2
\]
Number of moles of \(5 \mathrm{~g}\) of hydrogen \(=\frac{5}{1}\)
Number of atoms in \(5 \mathrm{~g}\) of hydrogen \(=5 \times \mathrm{N}_{0} \times 2\)
Hence, the number of atoms in \(80 \mathrm{~g}\) of oxygen is equal to the number of atoms in \(5 \mathrm{~g}\) of hydrogen.
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