JEE Mains · Physics · STD 12 - 3. current electricity
In the circuit diagram shown in figure given below, the current flowing through resistance \(3\, \Omega\) is \(\frac{ x }{3}\,A\). The value of \(x\) is \(...........\)
- A \(0.5\)
- B \(1\)
- C \(2\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{3}+\frac{1}{6}=\frac{1}{2}=\frac{1}{R}\) \(R =2\,\Omega\) \(I _1=\left(\frac{6}{3+6}\right) \times 0.5\) \(I _1=\frac{2}{3} \times 0.5=\frac{1}{3}\,A\) \(I _1=\frac{ x }{3}=\frac{1}{3} \therefore x =1\)
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