JEE Mains · Maths · STD 12 - 11. three dimension geometry
If the shortest distance between the line \(\vec{r}=(-\hat{i}+3 \hat{k})+\lambda(\hat{i}-a \hat{j})\) and \(\vec{r}=(-\hat{j}+2 \hat{k})+\mu(\hat{i}-\hat{j}+\hat{k})\) is \(\sqrt{\frac{2}{3}}\), then the integral value of \(a\) is equal to
- A \(5\)
- B \(2\)
- C \(3\)
- D \(7\)
Answer & Solution
Correct Answer
(A) \(5\)
Step-by-step Solution
Detailed explanation
\(a_{1}=(-1,0,3)\) \(a_{2}=(0,-1,2)\) \(b_{1}=(1,-a, 0)\) dr's of line (\(1\)) \(b_{2}=(1,-1,1)\) dr's of line \((2)\) \(\overline{ a }_{2}-\overline{ a }_{1}=(1,-1,-1)\)…
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