JEE Mains · Maths · STD 11 - 6. permutation and combination
There are \(15\) players in a cricket team, out of which \(6\) are bowlers, \(7\) are batsmen and \(2\) are wicketkeepers. The number of ways, a team of \(11\) players be selected from them so as to include at least \(4\) bowlers, \(5\) batsmen and \(1\) wicketkeeper, is \(.....\)
- A \(888\)
- B \(120\)
- C \(777\)
- D \(111\)
Answer & Solution
Correct Answer
(C) \(777\)
Step-by-step Solution
Detailed explanation
\(15:\) Players \(6:\) Bowlers \(7:\) Bastman \(2:\) Wicket keepers Total number of ways for: at least \(4\) bowlers, \(5\) bastsman \(\& 1\) wicket keeper \({ }^{6} C_{4} \cdot{ }^{7} C_{5} \cdot{ }^{2} C_{2}+{ }^{6} C_{4} \cdot^{7} C_{6} \cdot{ }^{2} C_{1}\)…
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