ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 9. differential equations

Let \(y=y(x)\) be the solution of the differential equation \(x d y=\left(y+x^{3} \cos x\right) d x\) with \(y(\pi)=0\) then \(y\left(\frac{\pi}{2}\right)\) is equal to :

  1. A \(\frac{\pi^{2}}{2}-\frac{\pi}{4}\)
  2. B \(\frac{\pi^{2}}{4}+\frac{\pi}{2}\)
  3. C \(\frac{\pi^{2}}{4}-\frac{\pi}{2}\)
  4. D \(\frac{\pi^{2}}{2}+\frac{\pi}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{\pi^{2}}{4}+\frac{\pi}{2}\)

Step-by-step Solution

Detailed explanation

\(x d y=\left(y+x^{3} \cos x\right) d x\) \(x d y=y d x+x^{3} \cos x d x\) \(\frac{x d y-y d x}{x^{2}}=\frac{x^{3} \cos x d x}{x^{2}}\) \(\int \frac{d}{d x}\left(\frac{y}{x}\right) d x=\int x \cos x d x\) \(\Rightarrow \frac{y}{x}=x \sin x-\int 1 \cdot \sin x d x\)…
From JEE Mains
Explore more questions on app