JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations
The sum of all real values of \(x\) for which \(\frac{3 x^{2}-9 x+17}{x^{2}+3 x+10}=\frac{5 x^{2}-7 x+19}{3 x^{2}+5 x+12}\) is equal to.
- A \(5\)
- B \(6\)
- C \(4\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(6\)
Step-by-step Solution
Detailed explanation
\(\frac{3 x^{2}-9 x+17}{x^{2}+3 x+10}=\frac{5 x^{2}-7 x+19}{3 x^{2}+5 x+12}\) \(\frac{x^{2}+3 x+10+2 x^{2}-12 x+7}{x^{2}+3 x+10}=\frac{3 x^{2}+5 x+12+2 x^{2}-12 x+7}{3 x^{2}+5 x+12}\) \(1+\frac{2 x^{2}-12 x+7}{x^{2}+3 x+10}=1+\frac{2 x^{2}-12 x+7}{3 x^{2}+5 x+12}\)…
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