JEE Mains · Maths · STD 11 - 6. permutation and combination
The number of natural numbers lying between \(1012\) and \(23421\) that can be formed using the digits \(2,3,4,5,6\) (repetition of digits is not allowed) and divisible by \(55\) is \(....\)
- A \(5\)
- B \(6\)
- C \(4\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(6\)
Step-by-step Solution
Detailed explanation
\(4\) digit numbers For divisibility by \(55\) , no. should be div. by \(5\) and \(11\) both Also, for divisibility by \(11\)…
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