JEE Mains · Maths · STD 12 - 11. three dimension geometry
The foot of the perpendicular drawn from the point \((4,2,3)\) to the line joining the points \((1,-2,3)\) and \((1,1,0)\) lies on the plane
- A \(x+2 y-z=1\)
- B \(x-2 y+z=1\)
- C \(x-y-2 z=1\)
- D \(2 x+y-z=1\)
Answer & Solution
Correct Answer
(D) \(2 x+y-z=1\)
Step-by-step Solution
Detailed explanation
Equation of \(AB =\overrightarrow{ r }=(\hat{ i }+\hat{ j })+\lambda(3 \hat{ j }-3 \hat{ k })\) Let coordinates of \(M =(1,(1+3 \lambda),-3 \lambda)\) \(\overrightarrow{ PM }=-3 \hat{i}+(3 \lambda-1) \hat{j}-3(\lambda+1) \hat{ k }\) \(\overline{ AB }=3 \hat{j}-3 \hat{ k }\)…
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