JEE Mains · Maths · STD 12 - 9. differential equations
The difference between degree and order of a differential equation that represents the family of curves given by \(y^{2}=a\left(x+\frac{\sqrt{a}}{2}\right), a>0\) is
- A \(4\)
- B \(3\)
- C \(4\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\(y ^{2}= a \left( x +\frac{\sqrt{ a }}{2}\right)= ax +\frac{ a ^{3 / 2}}{2}\) \(...(1)\) \(\Rightarrow 2 yy ^{\prime}= a\) put in equation (1) \(y^{2}=\left(2 y y^{\prime}\right) x+\frac{\left(2 y y^{\prime}\right)^{3 / 2}}{2}\)…
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