JEE Mains · Maths · STD 12 - 8. Application and integration
The area of the region given by \(A=\left\{(x, y): x^{2} \leq y \leq \min \{x+2,4-3 x\}\right\}\) is.
- A \(\frac{31}{8}\)
- B \(\frac{17}{6}\)
- C \(\frac{19}{6}\)
- D \(\frac{27}{8}\)
Answer & Solution
Correct Answer
(B) \(\frac{17}{6}\)
Step-by-step Solution
Detailed explanation
\(A=\int_{-1}^{\frac{1}{2}}\left(x+2-x^{2}\right) d x+\int_{\frac{1}{2}}^{1}\left(4-3 x-x^{2}\right) d x=\frac{17}{6}\)
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