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JEE Mains · Maths · STD 11 - 6. permutation and combination
The number of integers greater than \(6000\) that can be formed , using the digits \(3,5,6,7,\) and \( 8\) without repetition is :
- A \(72\)
- B \(216\)
- C \(192\)
- D \(120\)
Answer & Solution
Correct Answer
(C) \(192\)
Step-by-step Solution
Detailed explanation
case \(1\): \(5-\)digit no \(5!=120\) case \(2 :\) \(4\) digit \(\rightarrow 6000\) total \(4\) digit \(=3\times 4\times 3\times 2=72\) total \(5\) digit \(=120\) total no \(=120+72=192\)
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