JEE Mains · Maths · STD 12 - 8. Application and integration
The area (in sq. units) of the region enclosed between the parabola \(y ^{2}=2 x\) and the line \(x + y =4\) is
- A \(25\)
- B \(18\)
- C \(36\)
- D \(11\)
Answer & Solution
Correct Answer
(B) \(18\)
Step-by-step Solution
Detailed explanation
\(x=4-y\) \(y^{2}=2(4-y)\) \(y^{2}=8-2 y\) \(y^{2}+2 y-8=0\) \(y=-4, y=2\) \(x=8, x=2\) \(\int_{-4}^{2}\left[(4-y)-\frac{y^{2}}{2}\right] d y\) \(=\left[4 y-\frac{y^{2}}{2}-\frac{y^{3}}{6}\right]_{-4}^{2}\) \(=8-2-\frac{8}{6}+16+\frac{16}{2}-\frac{64}{6}\) \(=22+8-\frac{72}{6}\)…
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