JEE Mains · Maths · STD 11 - 9. straight line
lf a line \(L\) is perpendicular to the line \(5x - y\,= 1\) , and the area of the triangle formed by the line \(L\) and the coordinate axes is \(5\), then the distance of line \(L\) from the line \(x + 5y\, = 0\) is
- A \(\frac{7}{{\sqrt 5 }}\)
- B \(\frac{5}{{\sqrt {13} }}\)
- C \(\frac{7}{{\sqrt {13} }}\)
- D \(\frac{5}{{\sqrt 7 }}\)
Answer & Solution
Correct Answer
(B) \(\frac{5}{{\sqrt {13} }}\)
Step-by-step Solution
Detailed explanation
Let equation of line \(L\), perpendicular to \(5x-y=1\) be \(x+5y=c\) Given that are of \(\Delta AOB\) is \(5\). We know…
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