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JEE Mains · Maths · STD 12 - 9. differential equations

Let \(y=y(x)\) be the solution of the differential equation \(\sec \mathrm{x} d \mathrm{y}+\{2(1-\mathrm{x}) \tan \mathrm{x}+\mathrm{x}(2-\mathrm{x})\}\) \(\mathrm{dx}=0\) such that \(\mathrm{y}(0)=2\). Then \(\mathrm{y}(2)\) is equal to :

  1. A \(2\)
  2. B  \(2\{1-\sin (2)\}\)
  3. C \(2\{\sin (2)+1\}\)
  4. D \(1\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2\)

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}=2(x-1) \sin x+\left(x^2-2 x\right) \cos x\) Now both side integrate \( y(x)=\int 2(x-1) \sin x d x+\left[\left(x^2-2 x\right)(\sin x)-\int(2 x-2) \sin x d x\right] \) \( y(x)=\left(x^2-2 x\right) \sin x+\lambda\) \( y(0)=0+\lambda \Rightarrow 2=\lambda\)…
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