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JEE Mains · Maths · STD 12 - 7.2 definite integral
Let \(\{x\}\) and \([x]\) denote the fractional part of \(x\) and the greatest integer \(\leq x\) respectively of a real number \(x\). If \(\int \limits_{0}^{n}\{x\} d x, \int \limits_{0}^{n}[x] d x\) and \(10\left( n ^{2}- n \right),( n \in N , n >1)\) are three consecutive terms of a \(G.P.\), then \(n\) is equal to
- A \(20\)
- B \(18\)
- C \(21\)
- D \(23\)
Answer & Solution
Correct Answer
(C) \(21\)
Step-by-step Solution
Detailed explanation
\(\int_{0}^{n}\{x\} d x=n \int_{0}^{1}\{x\} d x=n \int_{0}^{1} x d x=\frac{n}{2}\) \(\int_{0}^{n}[x] d x=\int_{0}^{n}(x-\{x\}) d x=\frac{n^{2}}{2}-\frac{n}{2}\) \(\Rightarrow\left(\frac{n^{2}-n}{2}\right)^{2}=\frac{n}{2} \cdot 10 \cdot n(n-1)(\) where \(n>1)\)…
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