JEE Mains · Maths · STD 12 - 10. vector algebra
Let the vectors \(\overrightarrow{ u }_1=\hat{ i }+\hat{ j }+ a \hat{ k }, \overrightarrow{ u }_2=\hat{ i }+ b \hat{ j }+\hat{ k }\) and \(\overrightarrow{ u }_3=c \hat{ i }+\hat{ j }+\hat{ k }\) be coplanar. If the vectors \(\overrightarrow{ v }_1=(a+b) \hat{i}+c \hat{j}+c \hat{k}, \quad \overrightarrow{ v }_2=a \hat{i}+(b+c) \hat{j}+a \hat{k} \quad\) and \(\overrightarrow{ v }_3=b \hat{ i }+ b \hat{ j }+( c + a ) \hat{ k }\) are also coplanar, then \(6( a +\) \(b + c )\) is equal to \(..............\).
- A \(0\)
- B \(6\)
- C \(12\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(12\)
Step-by-step Solution
Detailed explanation
\({\left[\overrightarrow{ u }_1 \overrightarrow{ u }_2 \overrightarrow{ u }_3\right]=0 \quad \therefore\left|\begin{array}{lll}1 & 1 & a \\ 1 & b & 1 \\ c & 1 & 1\end{array}\right|=0}\) \(\Rightarrow b -1+ c -1+ a (1- bc )=0\) \(\therefore abc = a + b + c -2\)…
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