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JEE Mains · Maths · STD 11 - 12. limits

Let \([ t ]\) denote the greatest integer \(\leq t\). If for some \(\lambda \in R -\{0,1\}, \lim \limits_{x \rightarrow 0}\left|\frac{1-x+|x|}{\lambda-x+[x]}\right|=L,\) then \(L\) is equal to

  1. A \(1\)
  2. B \(2\)
  3. C \(\frac{1}{2}\)
  4. D \(0\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\(\operatorname{LHL}: \lim _{x \rightarrow 0^{-}}\left|\frac{1-x-x}{\lambda-x-1}\right|=\left|\frac{1}{\lambda-1}\right|\) \(\operatorname{RHL}: \lim _{x \rightarrow 0^{+}}\left|\frac{1-x+x}{\lambda-x+1}\right|=\left|\frac{1}{\lambda}\right|\) For existence of limitt…
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