JEE Mains · Maths · STD 11 - 6. permutation and combination
Let \(S\) be the set of all passwords which are six to eight characters long, where each character is either an alphabet from \(\{ A , B , C , D , E \}\) or a number from \(\{1,2,3,4,5\}\) with the repetition of characters allowed. If the number of passwords in \(S\) whose at least one character is a number from \(\{1,2,3,4,5\}\) is \(\alpha \times 5^{6}\), then \(\alpha\) is equal to \(.......\)
- A \(7075\)
- B \(7074\)
- C \(7073\)
- D \(7076\)
Answer & Solution
Correct Answer
(C) \(7073\)
Step-by-step Solution
Detailed explanation
Required no. \(=\) Total \(-\) no character from \(\{1,2,3,4,5\}\) \(=\left(10^{6}-5^{6}\right)+\left(10^{7}-5^{7}\right)+\left(10^{8}-5^{8}\right)\) \(=10^{6}(1+10+100)-5^{6}(1+5+25)\) \(=10^{6} \times 111-5^{6} \times 31\) \(=2^{6} \times 5^{6} \times 111-5^{6} \times 31\)…
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