JEE Mains · Maths · STD 12 - 7.2 definite integral
Let \(P ( x )= x ^{2}+ bx + c\) be a quadratic polynomial with real coefficients such that \(\int_{0}^{1} P ( x ) dx =1\) and \(P ( x )\) leaves remainder \(5\) when it is divided by \((x-2)\). Then the value of \(9(b+c)\) is equal to:
- A \(9\)
- B \(15\)
- C \(7\)
- D \(11\)
Answer & Solution
Correct Answer
(C) \(7\)
Step-by-step Solution
Detailed explanation
\(\int_{0}^{1}\left( x ^{2}+ bx + c \right) dx =1\) \(\frac{1}{3}+\frac{b}{2}+c=1 \quad \Rightarrow \quad \frac{b}{2}+c=\frac{2}{3}\) \(3 b+6 c=4.......(1)\) \(P (2)=5\) \(4+2 b+c=5\) \(2 b + c =1.......(2)\) From \((1)\) And \((2)\) \(b =\frac{2}{9}\) And \(c =\frac{5}{9}\)…
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