JEE Mains · Maths · STD 11 - 4.1 complex nubers
If \(S=\{z \in C:|z-i|=|z+i|=|z-1|\}\), then, \(n(S)\) is:
- A \(1\)
- B \(0\)
- C \(3\)
- D \(2\)
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
\(|z-i|=|z+i|=|z-1|\) \(\mathrm{ABC}\) is a triangle. Hence its circum-centre will be the only point whose distance from\( A\), \(B\), \(C\) will be same. So \(n(S)=1\)
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