JEE Mains · Maths · STD 12 - 10. vector algebra
Let (\( \alpha, \beta, \gamma \)) be the co-ordinates of the foot of the perpendicular drawn from the point (5, 4, 2) on the line \( \vec{r}=(-\hat{i}+3\hat{j}+\hat{k})+\lambda(2\hat{i}+3\hat{j}-\hat{k}) \). Then the length of the projection of the vector \( \alpha\hat{i}+\beta\hat{j}+\gamma\hat{k} \) on the vector \( 6\hat{i}+2\hat{j}+3\hat{k} \) is:
- A \( \frac{15}{7} \)
- B 4
- C \( \frac{18}{7} \)
- D 3
Answer & Solution
Correct Answer
(C) \( \frac{18}{7} \)
Step-by-step Solution
Detailed explanation
\(\overline{ r }=(-\hat{ i }+3 \hat{ j }+\hat{ k })+\lambda(2 \hat{ i }+3 \hat{ j }-\hat{ k })\) \( \frac{x+1}{2}=\frac{y-3}{3}=\frac{z-1}{-1}=\lambda \) Any general point P on the line is \( (2\lambda-1,3\lambda+3,-\lambda+1) \) Let the given point is A = (5,4,2).…
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