JEE Mains · Maths · STD 12 - 7.2 definite integral
Let \(a_{n}=\int_{-1}^{n}\left(1+\frac{x}{2}+\frac{x^{2}}{2}+\frac{x^{3}}{3}+\ldots \ldots .+\frac{x^{n-1}}{n}\right) d x\) for \(n \in N\). Then the sum of all the elements of the set \(\left\{n \in N: a_{n} \in(2,30)\right\}\) is \(...........\)
- A \(8\)
- B \(10\)
- C \(5\)
- D \(0\)
Answer & Solution
Correct Answer
(C) \(5\)
Step-by-step Solution
Detailed explanation
\(a_{n}=\int_{-1}^{n}\left(1+\frac{x}{2}+\frac{x^{2}}{3}+\ldots .+\frac{x^{n-1}}{n}\right) d x\) \(=\left[x+\frac{x^{2}}{2^{2}}+\frac{x^{3}}{3^{2}}+\ldots \ldots+\frac{x^{n}}{n^{2}}\right]_{-1}^{n}\)…
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