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JEE Mains · Maths · STD 12 - 10. vector algebra

Let \(\vec{a}, \vec{b}\) and \(\vec{c}\) be three vectors such that \(\vec{a}=\vec{b} \times(\vec{b} \times \vec{c}) .\) If magnitudes of the vectors \(\vec{a}, \vec{b}\) and \(\vec{c}\) are \(\sqrt{2}, 1\) and 2 respectively and the angle between \(\vec{b}\) and \(\vec{c}\) is \(\theta\left(0<\theta<\frac{\pi}{2}\right)\), then the value of \(1+\tan \theta\) is equal to:

  1. A \(\frac{\sqrt{3}+1}{\sqrt{3}}\)
  2. B \(2\)
  3. C \(\sqrt{3}+1\)
  4. D \(1\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\(\vec{a}=(\vec{b} \cdot \vec{c}) \vec{b}-(\vec{b} \cdot \vec{b}) \vec{c}\) \(=1.2 \cos \theta \vec{b}-\vec{c} b\) \(\Rightarrow \quad \vec{a}=2 \cos \theta \vec{b}-\vec{c}\) \(|\vec{a}|^{2}=(2 \cos \theta)^{2}+2^{2}-2 \cdot 2 \cos \theta \vec{b} \cdot \vec{c}\)…
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