JEE Mains · Maths · STD 12 - 9. differential equations
If \(x=x(t)\) is the solution of the differential equation \((t+1) d x=\left(2 x+(t+1)^4\right) d t, x(0)=2\), then \(x(1)\) equals ...........
- A \(14\)
- B \(15\)
- C \(16\)
- D \(17\)
Answer & Solution
Correct Answer
(A) \(14\)
Step-by-step Solution
Detailed explanation
\( (t+1) d x=\left(2 x+(t+1)^4\right) d t \) \( \frac{d x}{d t}=\frac{2 x+(t+1)^4}{t+1} \) \( \frac{d x}{d t}-\frac{2 x}{t+1}=(t+1)^3\) \( I \cdot F=e^{-\int \frac{2}{t+1} d t}=e^{-2 \ln (t+1)}=\frac{1}{(t+1)^2} \) \( \frac{x}{(t+1)^2}=\int \frac{1}{(t+1)^2}(t+1)^3 d t+c \)…
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