JEE Mains · Maths · STD 12 - 11. three dimension geometry
If the lines \(\frac{x-1}{1}=\frac{y-2}{2}=\frac{z+3}{1}\) and \(\frac{x-a}{2}=\frac{y+2}{3}=\frac{z-3}{1}\) intersects at the point \(P\), then the distance of the point \(P\) from the plane \(z = a\) is :
- A \(16\)
- B \(28\)
- C \(10\)
- D \(22\)
Answer & Solution
Correct Answer
(B) \(28\)
Step-by-step Solution
Detailed explanation
Point on \(L _1 \equiv(\lambda+1,2 \lambda+2, \lambda-3)\) Point on \(L _2 \equiv(2 \mu+ a , 3 \mu-2, \mu+3)\) \(\lambda-3=\mu+3\) \(\quad\Rightarrow \lambda=\mu+6\) \(2 \lambda+2=3 \mu-2\) \(\quad\Rightarrow 2 \lambda=3 \mu-4\) Solving,\((1)\) and \((2)\)…
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