JEE Mains · Maths · STD 12 - 11. three dimension geometry
If the line \(\frac{2-x}{3}=\frac{3 y-2}{4 \lambda+1}=4-z\) makes a right angle with the line \(\frac{x+3}{3 \mu}=\frac{1-2 y}{6}=\frac{5-z}{7}\), then \(4 \lambda+9 \mu\) is equal to :
- A \(13\)
- B \(4\)
- C \(5\)
- D \(6\)
Answer & Solution
Correct Answer
(D) \(6\)
Step-by-step Solution
Detailed explanation
\(\frac{2-x}{3}=\frac{3 y-2}{4 \lambda+1}=4-z\)................(\(1\)) \(\frac{x-2}{(-3)}=\frac{y-\frac{2}{3}}{\left(\frac{4 \lambda+1}{3}\right)}=\frac{z-4}{(-1)}\) \( \frac{x+3}{3 \mu}=\frac{1-2 y}{6}=\frac{5-z}{7} \)...................(\(2\))…
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